What is the integral from-1 to 1 of xe^x ?

The integral from-1 to 1 of xe^x is 2/e

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integral from-1 to 1 of xe^x

\int_{- 1}^{1} x e^{x} d x

\frac{2}{e}

Decimal Notation

0.73575 \dots

Solution steps

\int_{- 1}^{1} x e^{x} d x

Apply Integration By Parts

: [e^{x} x - \int e^{x} d x]_{- 1}^{1}

= [e^{x} x - \int e^{x} d x]_{- 1}^{1}

\int e^{x} d x = e^{x}

= [e^{x} x - e^{x}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{e}

= \frac{2}{e}

\frac{d}{d x} (ln (x^{2} + 3 x))

\frac{d}{d x} (5 (1 - e^{- 2 x}))

\frac{d}{d x} (x^{2} + y^{2} - 4)

x \to - 1 lim (\frac{x ^{2} + 1}{x + 1})

\int 6 x - x^{2} - 8 d x

What is the integral from-1 to 1 of xe^x ?
The integral from-1 to 1 of xe^x is 2/e