What is the tangent of sqrt(x),\at x=100 ?

The tangent of sqrt(x),\at x=100 is y= 1/20 x+5

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tangent of sqrt(x),\at x=100

tangent of

x, at x = 100

y = \frac{1}{20} x + 5

Solution steps

Find the tangent point:

(100, 10)

Find the slope of

y = x : \frac{d y}{d x} = \frac{1}{2 x}

Compute the slope of

y = x

x = 100 : m = \frac{1}{20}

Find the line with slope m=

\frac{1}{20}

and passing through

(100, 10) : y = \frac{1}{20} x + 5

y = \frac{1}{20} x + 5

2 t^{2}

\frac{d}{d x} (arctan (\frac{9}{x}))

f (x) = 5 x + 6, (6, 6)

\int (tan (3 x) + cot (3 x))^{2} d x

n = 0 \sum \infty \frac{5 ^{n}}{3 ^{n}}

What is the tangent of sqrt(x),\at x=100 ?
The tangent of sqrt(x),\at x=100 is y= 1/20 x+5