What is the derivative of (x^3/9) ?

The derivative of (x^3/9) is (x^2)/3

What is the first derivative of (x^3/9) ?

The first derivative of (x^3/9) is (x^2)/3

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\frac{d}{d x} (\frac{x ^{3}}{9})

\frac{x ^{2}}{3}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{9})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{9} \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{9} \cdot 3 x^{3 - 1}

Simplify

\frac{1}{9} \cdot 3 x^{3 - 1} : \frac{x ^{2}}{3}

= \frac{x ^{2}}{3}

\int_{2}^{6} \frac{x}{x - 2} d x

x^{4} + 8 x^{2} - x

f^{^{'}} (x) = x^{3} + 6 x^{2}

\frac{d y}{d x} = y^{2} x, y (0) = 6

y = 8 ln (x), y = x ln (x)

What is the derivative of (x^3/9) ?
The derivative of (x^3/9) is (x^2)/3
What is the first derivative of (x^3/9) ?
The first derivative of (x^3/9) is (x^2)/3