What is the integral from 2 to 6 of x/(x-2) ?

The integral from 2 to 6 of x/(x-2) is diverges

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integral from 2 to 6 of x/(x-2)

\int_{2}^{6} \frac{x}{x - 2} d x

diverges

Solution steps

\int_{2}^{6} \frac{x}{x - 2} d x

Apply u-substitution

: \int_{0}^{4} \frac{u + 2}{u} d u

= \int_{0}^{4} \frac{u + 2}{u} d u

Expand

\frac{u + 2}{u} : 1 + \frac{2}{u}

= \int_{0}^{4} 1 + \frac{2}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 1 d u + \int_{0}^{4} \frac{2}{u} d u

\int_{0}^{4} 1 d u = 4

\int_{0}^{4} \frac{2}{u} d u =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

x^{4} + 8 x^{2} - x

f^{^{'}} (x) = x^{3} + 6 x^{2}

\frac{d y}{d x} = y^{2} x, y (0) = 6

y = 8 ln (x), y = x ln (x)

(\frac{2}{π}) sin (π t), t

What is the integral from 2 to 6 of x/(x-2) ?
The integral from 2 to 6 of x/(x-2) is diverges