What is the solution for y^'+0.4*y=0.7*(299*e^{-0.7*x}) ?

The solution for y^'+0.4*y=0.7*(299*e^{-0.7*x}) is y=-(697.66666…)/(e^{0.7x)}+(c_{1})/(e^{0.4x)}

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y^'+0.4y=0.7(299e^{-0.7x})

y^{^{'}} + 0.4 \cdot y = 0.7 \cdot (299 \cdot e^{- 0.7 \cdot x})

y = - \frac{697.66666 \dots}{e ^{0.7 x}} + \frac{c _{1}}{e ^{0.4 x}}

Solution steps

y^{'} (x) + 0.4 \cdot y = 0.7 \cdot (299 \cdot e^{- 0.7 \cdot x})

Solve linear ODE:

y = - \frac{697.66666 \dots}{e ^{0.7 x}} + \frac{c _{1}}{e ^{0.4 x}}

y = - \frac{697.66666 \dots}{e ^{0.7 x}} + \frac{c _{1}}{e ^{0.4 x}}

x \to 1 + lim (2^{\frac{1}{x - 1}})

x (2 y - 3) d x + (x^{2} + 1) d y = 0

x \to 1 lim (7 x + a)

y^{^{'}} = \frac{2 y}{x}, y (2) = 4

(2 y^{2} + 6 x) d x + 2 x y d y = 0

What is the solution for y^'+0.4*y=0.7*(299*e^{-0.7*x}) ?
The solution for y^'+0.4*y=0.7*(299*e^{-0.7*x}) is y=-(697.66666…)/(e^{0.7x)}+(c_{1})/(e^{0.4x)}