What is the derivative of (2x+1)^3 ?

The derivative of (2x+1)^3 is 6(2x+1)^2

What is the first derivative of (2x+1)^3 ?

The first derivative of (2x+1)^3 is 6(2x+1)^2

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derivative of

(2 x + 1)^{3}

6 (2 x + 1)^{2}

Solution steps

\frac{d}{d x} ((2 x + 1)^{3})

Apply the chain rule:

3 (2 x + 1)^{2} \frac{d}{d x} (2 x + 1)

= 3 (2 x + 1)^{2} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= 3 (2 x + 1)^{2} \cdot 2

Simplify

= 6 (2 x + 1)^{2}

\int x^{2} sin (π x) d x

f (t) = e^{- 3 t} + 3

\frac{d}{d x} (x^{2} - ln (x))

sin (x^{2} + π)

2 x - \frac{1}{2 x}

What is the derivative of (2x+1)^3 ?
The derivative of (2x+1)^3 is 6(2x+1)^2
What is the first derivative of (2x+1)^3 ?
The first derivative of (2x+1)^3 is 6(2x+1)^2