What is (\partial ^2)/(\partial x\partial y)((1+2xy^2)^3) ?

The answer to (\partial ^2)/(\partial x\partial y)((1+2xy^2)^3) is 6(24x^2y^5+16xy^3+2y)

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(\partial ^2)/(\partial x\partial y)((1+2xy^2)^3)

\frac{\partial ^{2}}{\partial x \partial y} ((1 + 2 x y^{2})^{3})

6 (24 x^{2} y^{5} + 16 x y^{3} + 2 y)

Solution steps

\frac{\partial ^{2}}{\partial x \partial y} ((1 + 2 x y^{2})^{3})

\frac{\partial}{\partial x} ((1 + 2 x y^{2})^{3}) = 6 y^{2} (1 + 2 x y^{2})^{2}

= \frac{\partial}{\partial y} (6 y^{2} (1 + 2 x y^{2})^{2})

\frac{\partial}{\partial y} (6 y^{2} (1 + 2 x y^{2})^{2}) = 6 (24 x^{2} y^{5} + 16 x y^{3} + 2 y)

= 6 (24 x^{2} y^{5} + 16 x y^{3} + 2 y)

n = 1 \sum \infty 4 (2.1)^{n - 1}

\frac{d}{d x} (3 x^{2} 4^{- x})

t \frac{d y}{d t} = t^{3} + 8 t^{3} y

\int 9 cos (θ) d θ

\frac{d}{d x} (- 2 x^{2} + 7 x + 5)

What is (\partial ^2)/(\partial x\partial y)((1+2xy^2)^3) ?
The answer to (\partial ^2)/(\partial x\partial y)((1+2xy^2)^3) is 6(24x^2y^5+16xy^3+2y)