What is (\partial)/(\partial x)(sin^9(x)) ?

The answer to (\partial)/(\partial x)(sin^9(x)) is 9sin^8(x)cos(x)

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(\partial)/(\partial x)(sin^9(x))

\frac{\partial}{\partial x} (sin^{9} (x))

9 sin^{8} (x) cos (x)

Solution steps

\frac{\partial}{\partial x} (sin^{9} (x))

Apply the chain rule:

9 (sin (x))^{8} \frac{\partial}{\partial x} (sin (x))

= 9 (sin (x))^{8} \frac{\partial}{\partial x} (sin (x))

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= 9 (sin (x))^{8} cos (x)

Simplify

= 9 sin^{8} (x) cos (x)

\frac{\partial}{\partial y} (y \cdot cos (y - 2 x))

f (x) = x^{2} - x + 1

x \to 0 lim (x^{3})

\frac{d}{d x} ((3 x^{2} + 3 x - 1)^{4})

8 y^{^{''}} - 2 y^{^{'}} - y = 4 + 5 sin (2 t)

What is (\partial)/(\partial x)(sin^9(x)) ?
The answer to (\partial)/(\partial x)(sin^9(x)) is 9sin^8(x)cos(x)