What is the integral of 3xe^{5x^2} ?

The integral of 3xe^{5x^2} is 3/10 e^{5x^2}+C

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integral of 3xe^{5x^2}

\int 3 x e^{5 x^{2}} d x

\frac{3}{10} e^{5 x^{2}} + C

Solution steps

\int 3 x e^{5 x^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int x e^{5 x^{2}} d x

Apply u-substitution

: \int \frac{e ^{u}}{10} d u

= 3 \cdot \int \frac{e ^{u}}{10} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{10} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 3 \cdot \frac{1}{10} e^{u}

Substitute back

u = 5 x^{2}

= 3 \cdot \frac{1}{10} e^{5 x^{2}}

Simplify

3 \cdot \frac{1}{10} e^{5 x^{2}} : \frac{3}{10} e^{5 x^{2}}

= \frac{3}{10} e^{5 x^{2}}

Add a constant to the solution

= \frac{3}{10} e^{5 x^{2}} + C

\frac{d y}{d x} = \frac{2 x + sec ^{2} ( x )}{4 y}, y (π) = 1

\int_{2}^{3} 5 x d x

\frac{\partial}{\partial x} (sin (c t + 2 x))

\int lo g_{10} (x + 5) d x

What is the integral of 3xe^{5x^2} ?
The integral of 3xe^{5x^2} is 3/10 e^{5x^2}+C