What is the solution for (dy)/(dx)=(2x+sec^2(x))/(4y),y(pi)=1 ?

The solution for (dy)/(dx)=(2x+sec^2(x))/(4y),y(pi)=1 is y=sqrt((x^2+tan(x)-pi^2+2)/2)

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(dy)/(dx)=(2x+sec^2(x))/(4y),y(pi)=1

\frac{d y}{d x} = \frac{2 x + sec ^{2} ( x )}{4 y}, y (π) = 1

y = \frac{x ^{2} + tan ( x ) - π ^{2} + 2}{2}

Solution steps

\frac{d y}{d x} = \frac{2 x + sec ^{2} ( x )}{4 y}

Solve separable ODE:

y = \frac{x ^{2} + tan ( x ) - π ^{2} + 2}{2}

y = \frac{x ^{2} + tan ( x ) - π ^{2} + 2}{2}

\int_{2}^{3} 5 x d x

\frac{\partial}{\partial x} (sin (c t + 2 x))

\int lo g_{10} (x + 5) d x

\frac{\partial}{\partial x} (8 x^{6} y^{7} + 6 x^{4} y^{8})

What is the solution for (dy)/(dx)=(2x+sec^2(x))/(4y),y(pi)=1 ?
The solution for (dy)/(dx)=(2x+sec^2(x))/(4y),y(pi)=1 is y=sqrt((x^2+tan(x)-pi^2+2)/2)