What is the derivative of 8x^{-2} ?

The derivative of 8x^{-2} is -(16)/(x^3)

What is the first derivative of 8x^{-2} ?

The first derivative of 8x^{-2} is -(16)/(x^3)

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\frac{d}{d x} (8 x^{- 2})

- \frac{16}{x ^{3}}

Solution steps

\frac{d}{d x} (8 x^{- 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- 2 x^{- 2 - 1})

Simplify

8 (- 2 x^{- 2 - 1}) : - \frac{16}{x ^{3}}

= - \frac{16}{x ^{3}}

\int \frac{x ^{5} - 4 x ^{3}}{x} d x

\frac{( s + 5 )}{( s + 3 ) ( s + 7 )}

f (x) = 2 x - \frac{16}{x}

6 cos (x) + 3 sin^{2} (x)

\frac{d}{d x} (\frac{1}{2 x})

What is the derivative of 8x^{-2} ?
The derivative of 8x^{-2} is -(16)/(x^3)
What is the first derivative of 8x^{-2} ?
The first derivative of 8x^{-2} is -(16)/(x^3)