What is the derivative of f(x)=2x-(16)/(sqrt(x)) ?

The derivative of f(x)=2x-(16)/(sqrt(x)) is 2+8/(x^{3/2)}

What is the first derivative of f(x)=2x-(16)/(sqrt(x)) ?

The first derivative of f(x)=2x-(16)/(sqrt(x)) is 2+8/(x^{3/2)}

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derivative of

f (x) = 2 x - \frac{16}{x}

2 + \frac{8}{x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (2 x - \frac{16}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (\frac{16}{x})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (\frac{16}{x}) = - \frac{8}{x ^{\frac{3}{2}}}

= 2 - (- \frac{8}{x ^{\frac{3}{2}}})

Simplify

= 2 + \frac{8}{x ^{\frac{3}{2}}}

6 cos (x) + 3 sin^{2} (x)

\frac{d}{d x} (\frac{1}{2 x})

\frac{d}{d x} (2 x + x)

\frac{d}{d x} (x^{4} - 4 x^{2})

\frac{d y}{d t} + e^{t} y = 9 e^{t}

What is the derivative of f(x)=2x-(16)/(sqrt(x)) ?
The derivative of f(x)=2x-(16)/(sqrt(x)) is 2+8/(x^{3/2)}
What is the first derivative of f(x)=2x-(16)/(sqrt(x)) ?
The first derivative of f(x)=2x-(16)/(sqrt(x)) is 2+8/(x^{3/2)}