What is the derivative of 1/(sqrt(2\sqrt{x)}) ?

The derivative of 1/(sqrt(2\sqrt{x)}) is -1/(2sqrt(2)x^{3/2)}

What is the first derivative of 1/(sqrt(2\sqrt{x)}) ?

The first derivative of 1/(sqrt(2\sqrt{x)}) is -1/(2sqrt(2)x^{3/2)}

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\frac{d}{d x} (\frac{1}{2 x})

- \frac{1}{2 2 x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} (x^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- \frac{1}{2} x^{- \frac{1}{2} - 1})

Simplify

\frac{1}{2} (- \frac{1}{2} x^{- \frac{1}{2} - 1}) : - \frac{1}{2 2 x ^{\frac{3}{2}}}

= - \frac{1}{2 2 x ^{\frac{3}{2}}}

\frac{d}{d x} (2 x + x)

\frac{d}{d x} (x^{4} - 4 x^{2})

\frac{d y}{d t} + e^{t} y = 9 e^{t}

\frac{d y}{d x} = 6 y^{2} x

y = x^{2} - 5 x + 3, (2, - 3)

What is the derivative of 1/(sqrt(2\sqrt{x)}) ?
The derivative of 1/(sqrt(2\sqrt{x)}) is -1/(2sqrt(2)x^{3/2)}
What is the first derivative of 1/(sqrt(2\sqrt{x)}) ?
The first derivative of 1/(sqrt(2\sqrt{x)}) is -1/(2sqrt(2)x^{3/2)}