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Popular >

area y=-2x^2+6,y=-2

Solution

area

y = - 2 x^{2} + 6, y = - 2

Solution

\frac{64}{3}

+1

Decimal Notation

21.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} - 2 x^{2} + 8 d x

Solve

\int_{- 2}^{2} - 2 x^{2} + 8 d x : \frac{64}{3}

The area is:

= \frac{64}{3}

Popular Examples

integral of 1/(sin^2(x)\sqrt[4]{cot(x))}

integral of sqrt(1+x^2)*x^5

\int 1 + x^{2} \cdot x^{5} d x

tangent of y=-x^3+2x^2-4,\at x=-1 tangent of

y = - x^{3} + 2 x^{2} - 4, at x = - 1

derivative of-sec^2(x)derivative of

- sec^{2} (x)

d/(dn)(e^{nipi})

\frac{d}{d n} (e^{niπ})

Frequently Asked Questions (FAQ)

What is area y=-2x^2+6,y=-2 ?
The answer to area y=-2x^2+6,y=-2 is 64/3