What is the tangent of f(x)=e^x,\at x=ln(12) ?

The tangent of f(x)=e^x,\at x=ln(12) is y=12x+12-12ln(12)

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tangent of f(x)=e^x,\at x=ln(12)

tangent of

f (x) = e^{x}, at x = ln (12)

y = 12 x + 12 - 12 ln (12)

Solution steps

Find the tangent point:

(ln (12), 12)

Find the slope of

f (x) = e^{x} : \frac{df ( x )}{d x} = e^{x}

Compute the slope of

f (x) = e^{x}

x = ln (12) : m = 12

Find the line with slope m=

12

and passing through

(ln (12), 12) : y = 12 x + 12 - 12 ln (12)

y = 12 x + 12 - 12 ln (12)

x \to 1 lim (x^{3} - x^{2} + 4 x)

sin (2 x + 3)

\frac{d}{d x} ((8 x + 5)^{2})

y = 5 x - 2 x^{2}, (- 2, - 18)

\frac{d}{d x} (\frac{x + 7}{x - 7})

What is the tangent of f(x)=e^x,\at x=ln(12) ?
The tangent of f(x)=e^x,\at x=ln(12) is y=12x+12-12ln(12)