What is the derivative of (x^2-1(x^2-4)(x^2-9)) ?

The derivative of (x^2-1(x^2-4)(x^2-9)) is 6x^5-56x^3+98x

What is the first derivative of (x^2-1(x^2-4)(x^2-9)) ?

The first derivative of (x^2-1(x^2-4)(x^2-9)) is 6x^5-56x^3+98x

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\frac{d}{d x} ((x^{2} - 1) (x^{2} - 4) (x^{2} - 9))

6 x^{5} - 56 x^{3} + 98 x

Solution steps

\frac{d}{d x} ((x^{2} - 1) (x^{2} - 4) (x^{2} - 9))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2} - 1, g = (x^{2} - 4) (x^{2} - 9)

= \frac{d}{d x} (x^{2} - 1) (x^{2} - 4) (x^{2} - 9) + \frac{d}{d x} ((x^{2} - 4) (x^{2} - 9)) (x^{2} - 1)

\frac{d}{d x} (x^{2} - 1) = 2 x

\frac{d}{d x} ((x^{2} - 4) (x^{2} - 9)) = 4 x^{3} - 26 x

= 2 x (x^{2} - 4) (x^{2} - 9) + (4 x^{3} - 26 x) (x^{2} - 1)

Simplify

2 x (x^{2} - 4) (x^{2} - 9) + (4 x^{3} - 26 x) (x^{2} - 1) : 6 x^{5} - 56 x^{3} + 98 x

= 6 x^{5} - 56 x^{3} + 98 x

\frac{\partial}{\partial x} (50 - (4 x^{2} + y^{2}))

\frac{d}{d x} (1 - cos (x))

y^{'} = 0.0013 y (3000 - y)

y = 3 x^{3} - x^{2} + 7, (2, 27)

\int (x + 4) (x + 2) d x

What is the derivative of (x^2-1(x^2-4)(x^2-9)) ?
The derivative of (x^2-1(x^2-4)(x^2-9)) is 6x^5-56x^3+98x
What is the first derivative of (x^2-1(x^2-4)(x^2-9)) ?
The first derivative of (x^2-1(x^2-4)(x^2-9)) is 6x^5-56x^3+98x