What is the limit as x approaches 6+of (8+x)/(6-x) ?

The limit as x approaches 6+of (8+x)/(6-x) is -infinity

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limit as x approaches 6+of (8+x)/(6-x)

x \to 6 + lim (\frac{8 + x}{6 - x})

- \infty

Solution steps

x \to 6 + lim (\frac{8 + x}{6 - x})

\frac{8 + x}{6 - x} = (8 + x) \frac{1}{6 - x}

= x \to 6 + lim ((8 + x) \frac{1}{6 - x})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 6 + lim (8 + x) \cdot x \to 6 + lim (\frac{1}{6 - x})

x \to 6 + lim (8 + x) = 14

x \to 6 + lim (\frac{1}{6 - x}) = - \infty

= 14 (- \infty)

Apply Infinity Property:

c \cdot (- \infty) = - \infty

= - \infty

\int x^{3} e^{(x^{2})} d x

\int (8 x + 3) d x

\frac{\partial}{\partial y} (e^{x y} ln (y))

\frac{3}{1 - 6 x}

y^{^{'}} = e^{- 3 x}

What is the limit as x approaches 6+of (8+x)/(6-x) ?
The limit as x approaches 6+of (8+x)/(6-x) is -infinity