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Popular >

1/2 y^'+2y=0

Solution

\frac{1}{2} y^{^{'}} + 2 y = 0

Solution

y = e^{- 4 t + c_{1}}

Solution steps

\frac{1}{2} y^{'} (t) + 2 y = 0

Solve separable ODE:

y = e^{- 4 t + c_{1}}

y = e^{- 4 t + c_{1}}

Popular Examples

integral from x to infinity of 2e^{-x-y}

\int_{x}^{\infty} 2 e^{- x - y} d y

integral of (8x-7)ln(x)

\int (8 x - 7) ln (x) d x

derivative of y=4x^2-13x-9/(x^4)derivative of

y = 4 x^{2} - 13 x - \frac{9}{x ^{4}}

tangent of f(x)= 2/x ,(-3,-2/3)tangent of

f (x) = \frac{2}{x}, (- 3, - \frac{2}{3})

derivative of x-ln(x^2)

\frac{d}{d x} (x - ln (x^{2}))

Frequently Asked Questions (FAQ)

What is the solution for 1/2 y^'+2y=0 ?
The solution for 1/2 y^'+2y=0 is y=e^{-4t+c_{1}}