What is the tangent of f(x)= 2/x ,(-3,-2/3) ?

The tangent of f(x)= 2/x ,(-3,-2/3) is y=-2/9 x-4/3

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tangent of f(x)= 2/x ,(-3,-2/3)

tangent of

f (x) = \frac{2}{x}, (- 3, - \frac{2}{3})

y = - \frac{2}{9} x - \frac{4}{3}

Solution steps

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

f (x) = \frac{2}{x}

(- 3, - \frac{2}{3}) : m = - \frac{2}{9}

Find the line with slope m=

- \frac{2}{9}

and passing through

(- 3, - \frac{2}{3}) : y = - \frac{2}{9} x - \frac{4}{3}

y = - \frac{2}{9} x - \frac{4}{3}

\frac{d}{d x} (x - ln (x^{2}))

\int - \frac{3}{x} d x

f (x) = (x - 1) (x^{2} + 2)^{3}

\int sin (x) cos (x) d x

\frac{\partial}{\partial y} (e^{x} \cdot cos (y))

What is the tangent of f(x)= 2/x ,(-3,-2/3) ?
The tangent of f(x)= 2/x ,(-3,-2/3) is y=-2/9 x-4/3