What is the derivative of x-ln(x^2) ?

The derivative of x-ln(x^2) is 1-2/x

What is the first derivative of x-ln(x^2) ?

The first derivative of x-ln(x^2) is 1-2/x

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\frac{d}{d x} (x - ln (x^{2}))

1 - \frac{2}{x}

Solution steps

\frac{d}{d x} (x - ln (x^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (ln (x^{2}))

\frac{d x}{d x} = 1

\frac{d}{d x} (ln (x^{2})) = \frac{2}{x}

= 1 - \frac{2}{x}

\int - \frac{3}{x} d x

f (x) = (x - 1) (x^{2} + 2)^{3}

\int sin (x) cos (x) d x

\frac{\partial}{\partial y} (e^{x} \cdot cos (y))

ln (2 x), 1

What is the derivative of x-ln(x^2) ?
The derivative of x-ln(x^2) is 1-2/x
What is the first derivative of x-ln(x^2) ?
The first derivative of x-ln(x^2) is 1-2/x