What is the derivative of (3x^2+3x-1)^4 ?

The derivative of (3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)

What is the first derivative of (3x^2+3x-1)^4 ?

The first derivative of (3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)

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derivative of

(3 x^{2} + 3 x - 1)^{4}

4 (3 x^{2} + 3 x - 1)^{3} (6 x + 3)

Solution steps

\frac{d}{d x} ((3 x^{2} + 3 x - 1)^{4})

Apply the chain rule:

4 (3 x^{2} + 3 x - 1)^{3} \frac{d}{d x} (3 x^{2} + 3 x - 1)

= 4 (3 x^{2} + 3 x - 1)^{3} \frac{d}{d x} (3 x^{2} + 3 x - 1)

\frac{d}{d x} (3 x^{2} + 3 x - 1) = 6 x + 3

= 4 (3 x^{2} + 3 x - 1)^{3} (6 x + 3)

10 \frac{d ^{2} y}{d x ^{2}} + 3 \frac{d y}{d x} + 6 y = 0

n = 2 \sum \infty \frac{2}{n ^{2} + 4 n + 3}

\frac{1}{∣ 1 - x ∣}

\frac{d y}{d x} = \frac{3 ( 2 + y )}{( 3 - x ) ^{2}}, y (0) = - 1

\int_{- \infty}^{1} e^{x} d x

What is the derivative of (3x^2+3x-1)^4 ?
The derivative of (3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)
What is the first derivative of (3x^2+3x-1)^4 ?
The first derivative of (3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)