What is the integral from-infinity to 1 of e^x ?

The integral from-infinity to 1 of e^x is e

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integral from-infinity to 1 of e^x

\int_{- \infty}^{1} e^{x} d x

e

Decimal Notation

2.71828 \dots

Solution steps

\int_{- \infty}^{1} e^{x} d x

Compute the indefinite integral:

\int e^{x} d x = e^{x} + C

Compute the boundaries:

\int_{- \infty}^{1} e^{x} d x = e - 0

= e - 0

Simplify

= e

\frac{\partial}{\partial x} (x^{0.5} y^{0.5})

\frac{\partial}{\partial x} (sin (- 6 x - 3 y))

y = 3 x + 5

n = 0 \sum \infty \frac{n}{8 ^{n}}

What is the integral from-infinity to 1 of e^x ?
The integral from-infinity to 1 of e^x is e