What is the solution for (dy)/(dx)=(3(2+y))/((3-x)^2),y(0)=-1 ?

The solution for (dy)/(dx)=(3(2+y))/((3-x)^2),y(0)=-1 is y=e^{3/(3-x)-1}-2

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(dy)/(dx)=(3(2+y))/((3-x)^2),y(0)=-1

\frac{d y}{d x} = \frac{3 ( 2 + y )}{( 3 - x ) ^{2}}, y (0) = - 1

y = e^{\frac{3}{3 - x} - 1} - 2

Solution steps

\frac{d y}{d x} = \frac{3 ( 2 + y )}{( 3 - x ) ^{2}}

Solve separable ODE:

y = e^{\frac{3}{3 - x} - 1} - 2

y = e^{\frac{3}{3 - x} - 1} - 2

\int_{- \infty}^{1} e^{x} d x

\frac{\partial}{\partial x} (x^{0.5} y^{0.5})

\frac{\partial}{\partial x} (sin (- 6 x - 3 y))

y = 3 x + 5

What is the solution for (dy)/(dx)=(3(2+y))/((3-x)^2),y(0)=-1 ?
The solution for (dy)/(dx)=(3(2+y))/((3-x)^2),y(0)=-1 is y=e^{3/(3-x)-1}-2