What is the derivative of (-16x^2+36)^2 ?

The derivative of (-16x^2+36)^2 is -64x(-16x^2+36)

What is the first derivative of (-16x^2+36)^2 ?

The first derivative of (-16x^2+36)^2 is -64x(-16x^2+36)

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derivative of

(- 16 x^{2} + 36)^{2}

- 64 x (- 16 x^{2} + 36)

Solution steps

\frac{d}{d x} ((- 16 x^{2} + 36)^{2})

Apply the chain rule:

2 (- 16 x^{2} + 36) \frac{d}{d x} (- 16 x^{2} + 36)

= 2 (- 16 x^{2} + 36) \frac{d}{d x} (- 16 x^{2} + 36)

\frac{d}{d x} (- 16 x^{2} + 36) = - 32 x

= 2 (- 16 x^{2} + 36) (- 32 x)

Simplify

= - 64 x (- 16 x^{2} + 36)

\frac{d}{d x} (cos (3 x^{2} + x - 1))

\frac{d}{d x} (ln (x) + \frac{x - 1}{x})

\int cos (- 3 x) d x

x y^{3} + 5 x y = 36, (6, 1)

\frac{\partial}{\partial x} (3 e x sin (y))

What is the derivative of (-16x^2+36)^2 ?
The derivative of (-16x^2+36)^2 is -64x(-16x^2+36)
What is the first derivative of (-16x^2+36)^2 ?
The first derivative of (-16x^2+36)^2 is -64x(-16x^2+36)