What is the derivative of (x^3-7/(x^2+2)) ?

The derivative of (x^3-7/(x^2+2)) is (x^4+6x^2+14x)/((x^2+2)^2)

What is the first derivative of (x^3-7/(x^2+2)) ?

The first derivative of (x^3-7/(x^2+2)) is (x^4+6x^2+14x)/((x^2+2)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{x ^{3} - 7}{x ^{2} + 2})

\frac{x ^{4} + 6 x ^{2} + 14 x}{( x ^{2} + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3} - 7}{x ^{2} + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{3} - 7 ) ( x ^{2} + 2 ) - \frac{d}{d x} ( x ^{2} + 2 ) ( x ^{3} - 7 )}{( x ^{2} + 2 ) ^{2}}

\frac{d}{d x} (x^{3} - 7) = 3 x^{2}

\frac{d}{d x} (x^{2} + 2) = 2 x

= \frac{3 x ^{2} ( x ^{2} + 2 ) - 2 x ( x ^{3} - 7 )}{( x ^{2} + 2 ) ^{2}}

Expand

3 x^{2} (x^{2} + 2) - 2 x (x^{3} - 7) : x^{4} + 6 x^{2} + 14 x

= \frac{x ^{4} + 6 x ^{2} + 14 x}{( x ^{2} + 2 ) ^{2}}

\frac{d ^{3}}{d x ^{3}} (\frac{1}{1 - x})

\frac{d}{d x} (3 x^{2} + 2 x - 4)

\int \frac{x}{( 4 + x ^{2} )} d x

\int \frac{( 3 t - 2 )}{t + 1} d t

What is the derivative of (x^3-7/(x^2+2)) ?
The derivative of (x^3-7/(x^2+2)) is (x^4+6x^2+14x)/((x^2+2)^2)
What is the first derivative of (x^3-7/(x^2+2)) ?
The first derivative of (x^3-7/(x^2+2)) is (x^4+6x^2+14x)/((x^2+2)^2)