What is the integral of 1/((y+1)) ?

The integral of 1/((y+1)) is ln|y+1|+C

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integral of 1/((y+1))

\int \frac{1}{( y + 1 )} d y

ln ∣ y + 1 ∣ + C

Solution steps

\int \frac{1}{y + 1} d y

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = y + 1

= ln ∣ y + 1 ∣

Add a constant to the solution

= ln ∣ y + 1 ∣ + C

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