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Popular >

y^'=1

Solution

y^{^{'}} = 1

Solution

y = t + c_{1}

Solution steps

y^{'} (t) = 1

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 1 d t

\int 1 d t = t + c_{1}

y = t + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=1 ?
The solution for y^'=1 is y=t+c_{1}