What is the tangent of y=x^2e^{-x},(1, 1/e) ?

The tangent of y=x^2e^{-x},(1, 1/e) is y= 1/e x

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tangent of y=x^2e^{-x},(1, 1/e)

tangent of

y = x^{2} e^{- x}, (1, \frac{1}{e})

y = \frac{1}{e} x

Solution steps

Find the slope of

y = x^{2} e^{- x} : \frac{d y}{d x} = 2 e^{- x} x - e^{- x} x^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{e}

Find the line with slope m=

\frac{1}{e}

and passing through

(1, \frac{1}{e}) : y = \frac{1}{e} x

y = \frac{1}{e} x

\frac{d}{d x} (3^{x})

\int \frac{1}{x ^{2} - 289} d x

\int_{0}^{1} \frac{5}{x ^{2} + 1} d x

\int (\frac{3}{x} + 2 e^{x}) d x

8 x^{2} y^{^{'}} = y^{^{'}} + 9 x e^{- y}

What is the tangent of y=x^2e^{-x},(1, 1/e) ?
The tangent of y=x^2e^{-x},(1, 1/e) is y= 1/e x