What is the integral of (3/x+2e^x) ?

The integral of (3/x+2e^x) is 3ln|x|+2e^x+C

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integral of (3/x+2e^x)

\int (\frac{3}{x} + 2 e^{x}) d x

3 ln ∣ x ∣ + 2 e^{x} + C

Solution steps

\int \frac{3}{x} + 2 e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3}{x} d x + \int 2 e^{x} d x

\int \frac{3}{x} d x = 3 ln ∣ x ∣

\int 2 e^{x} d x = 2 e^{x}

= 3 ln ∣ x ∣ + 2 e^{x}

Add a constant to the solution

= 3 ln ∣ x ∣ + 2 e^{x} + C

8 x^{2} y^{^{'}} = y^{^{'}} + 9 x e^{- y}

x^{2}, 12 - x, [- 3, 4]

x \to - 0 lim (e^{\frac{1}{x}})

\frac{d}{d x} (c^{1} cos (x) + c^{2} sin (x))

x \to - 4 lim (12 x + 1)

What is the integral of (3/x+2e^x) ?
The integral of (3/x+2e^x) is 3ln|x|+2e^x+C