What is (\partial}{\partial u}(\frac{(v-u))/2) ?

The answer to (\partial}{\partial u}(\frac{(v-u))/2) is -1/2

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(\partial}{\partial u}(\frac{(v-u))/2)

\frac{\partial}{\partial u} (\frac{( v - u )}{2})

- \frac{1}{2}

Solution steps

\frac{\partial}{\partial u} (\frac{( v - u )}{2})

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{\partial}{\partial u} (v - u)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{\partial}{\partial u} (v) - \frac{\partial}{\partial u} (u))

\frac{\partial}{\partial u} (v) = 0

\frac{\partial}{\partial u} (u) = 1

= \frac{1}{2} (0 - 1)

Simplify

= - \frac{1}{2}

x d y = (x sin (x) - y) d x

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3 x^{2} + 2 x - 10

What is (\partial}{\partial u}(\frac{(v-u))/2) ?
The answer to (\partial}{\partial u}(\frac{(v-u))/2) is -1/2