What is (\partial)/(\partial x)(x^2-y^2) ?

The answer to (\partial)/(\partial x)(x^2-y^2) is 2x

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(\partial)/(\partial x)(x^2-y^2)

\frac{\partial}{\partial x} (x^{2} - y^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 x - 0

Simplify

= 2 x

\int (tan (\frac{x}{10}))^{5} d x

(1 - e^{2 y}) \frac{d y}{d x} = e^{y}

x^{2} + y^{2} = 25, (- 4, - 3)

\int 2 x sin (x^{2}) d x

y^{^{'}} + \frac{y ^{2}}{x} = - \frac{1}{x}

What is (\partial)/(\partial x)(x^2-y^2) ?
The answer to (\partial)/(\partial x)(x^2-y^2) is 2x