What is the (-7sqrt(2)sin(t))^' ?

The (-7sqrt(2)sin(t))^' is -7sqrt(2)cos(t)

What is the first (-7sqrt(2)sin(t))^' ?

The first (-7sqrt(2)sin(t))^' is -7sqrt(2)cos(t)

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(- 72 sin (t))^{^{'}}

- 72 cos (t)

Solution steps

(- 72 sin (t))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 72 (sin (t))^{^{'}}

Apply the common derivative:

(sin (t))^{'} = cos (t)

= - 72 cos (t)

y = 2 x^{3}

\frac{d}{d x} (f (x) (x)^{n})

\int \frac{x ^{5} - x ^{3} + 6 x}{x ^{4}} d x

\frac{d}{d x} (sin (3 x^{3} + 2))

\frac{d}{d x} (2 x + \frac{1}{x ^{2}})

What is the (-7sqrt(2)sin(t))^' ?
The (-7sqrt(2)sin(t))^' is -7sqrt(2)cos(t)
What is the first (-7sqrt(2)sin(t))^' ?
The first (-7sqrt(2)sin(t))^' is -7sqrt(2)cos(t)