What is the derivative of 3sin(x-x) ?

The derivative of 3sin(x-x) is 3cos(x)-1

What is the first derivative of 3sin(x-x) ?

The first derivative of 3sin(x-x) is 3cos(x)-1

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\frac{d}{d x} (3 sin (x) - x)

3 cos (x) - 1

Solution steps

\frac{d}{d x} (3 sin (x) - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 sin (x)) - \frac{d x}{d x}

\frac{d}{d x} (3 sin (x)) = 3 cos (x)

\frac{d x}{d x} = 1

= 3 cos (x) - 1

\frac{\partial}{\partial x} (3 x^{2} + 3 y^{2})

\int (- 5) d x

\int \frac{t}{( t ^{2} + 1 ) ^{\frac{25}{2}}} d t

x^{3} + 6 x^{2} + 8 x, [- 4, 0]

\frac{\partial}{\partial x} (- x^{3} - y^{2} + 3 x^{2} - 10 y - 6)

What is the derivative of 3sin(x-x) ?
The derivative of 3sin(x-x) is 3cos(x)-1
What is the first derivative of 3sin(x-x) ?
The first derivative of 3sin(x-x) is 3cos(x)-1