What is the derivative of ln(sqrt(1-2x)) ?

The derivative of ln(sqrt(1-2x)) is -1/(1-2x)

What is the first derivative of ln(sqrt(1-2x)) ?

The first derivative of ln(sqrt(1-2x)) is -1/(1-2x)

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derivative of

ln (1 - 2 x)

- \frac{1}{1 - 2 x}

Solution steps

\frac{d}{d x} (ln (1 - 2 x))

Apply the chain rule:

\frac{1}{1 - 2 x} \frac{d}{d x} (1 - 2 x)

= \frac{1}{1 - 2 x} \frac{d}{d x} (1 - 2 x)

\frac{d}{d x} (1 - 2 x) = - \frac{1}{1 - 2 x}

= \frac{1}{1 - 2 x} (- \frac{1}{1 - 2 x})

Simplify

\frac{1}{1 - 2 x} (- \frac{1}{1 - 2 x}) : - \frac{1}{1 - 2 x}

= - \frac{1}{1 - 2 x}

\int_{0}^{- \frac{π}{2}} sin^{5} (x) d x

\int (10 x)^{n} d x

\int_{2}^{5} 2 x^{3} d x

\frac{d y}{d x} = - y^{3}

y = x^{2} - 8 x + 9, (1, 2)

What is the derivative of ln(sqrt(1-2x)) ?
The derivative of ln(sqrt(1-2x)) is -1/(1-2x)
What is the first derivative of ln(sqrt(1-2x)) ?
The first derivative of ln(sqrt(1-2x)) is -1/(1-2x)