What is the derivative of (1+7x^2(x-x^2)) ?

The derivative of (1+7x^2(x-x^2)) is -28x^3+21x^2-2x+1

What is the first derivative of (1+7x^2(x-x^2)) ?

The first derivative of (1+7x^2(x-x^2)) is -28x^3+21x^2-2x+1

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\frac{d}{d x} ((1 + 7 x^{2}) (x - x^{2}))

- 28 x^{3} + 21 x^{2} - 2 x + 1

Solution steps

\frac{d}{d x} ((1 + 7 x^{2}) (x - x^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 1 + 7 x^{2}, g = x - x^{2}

= \frac{d}{d x} (1 + 7 x^{2}) (x - x^{2}) + \frac{d}{d x} (x - x^{2}) (1 + 7 x^{2})

\frac{d}{d x} (1 + 7 x^{2}) = 14 x

\frac{d}{d x} (x - x^{2}) = 1 - 2 x

= 14 x (x - x^{2}) + (1 - 2 x) (1 + 7 x^{2})

Simplify

14 x (x - x^{2}) + (1 - 2 x) (1 + 7 x^{2}) : - 28 x^{3} + 21 x^{2} - 2 x + 1

= - 28 x^{3} + 21 x^{2} - 2 x + 1

\int_{- 5}^{5} x (25 - x^{2}) d x

\int 7 x^{2} + 3 x - 3 d x

\frac{\partial}{\partial x} (2 y e^{2 x y})

f (x) = \frac{x}{1 - ln ( x - 6 )}

2 x + 2 y \frac{d y}{d x} = 0

What is the derivative of (1+7x^2(x-x^2)) ?
The derivative of (1+7x^2(x-x^2)) is -28x^3+21x^2-2x+1
What is the first derivative of (1+7x^2(x-x^2)) ?
The first derivative of (1+7x^2(x-x^2)) is -28x^3+21x^2-2x+1