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Popular >

y^'+1/x y=9x^2

Solution

y^{^{'}} + \frac{1}{x} y = 9 x^{2}

Solution

y = \frac{9 x ^{3}}{4} + \frac{c _{1}}{x}

Solution steps

y^{'} (x) + \frac{1}{x} y = 9 x^{2}

Solve linear ODE:

y = \frac{9 x ^{3}}{4} + \frac{c _{1}}{x}

y = \frac{9 x ^{3}}{4} + \frac{c _{1}}{x}

Popular Examples

(\partial)/(\partial x)(x^2ln(y+1))

\frac{\partial}{\partial x} (x^{2} ln (y + 1))

area 3sqrt(x),x area

3 x, x

integral of (sec^2(3x))/(1+tan(3x))

\int \frac{sec ^{2} ( 3 x )}{1 + tan ( 3 x )} d x

slope of y=x^2-3x-5,(2,-7)slope

y = x^{2} - 3 x - 5, (2, - 7)

tangent of f(x)=3x^2-12x+1,(0,1)tangent of

f (x) = 3 x^{2} - 12 x + 1, (0, 1)

Frequently Asked Questions (FAQ)

What is the solution for y^'+1/x y=9x^2 ?
The solution for y^'+1/x y=9x^2 is y=(9x^3)/4+(c_{1})/x