What is (\partial)/(\partial y)(y/2) ?

The answer to (\partial)/(\partial y)(y/2) is 1/2

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(\partial)/(\partial y)(y/2)

\frac{\partial}{\partial y} (\frac{y}{2})

\frac{1}{2}

Solution steps

\frac{\partial}{\partial y} (\frac{y}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= \frac{1}{2} \cdot 1

Simplify

= \frac{1}{2}

f (x) = 3 x^{2} - 1

\frac{d y}{d x} = x + 6 y, y (0) = 2

f (x) = \frac{4 x + 5}{x - 1}, (2, 13)

2 x, 2 x

n = 1 \sum \infty (\frac{1}{2})^{2 n - 1}

What is (\partial)/(\partial y)(y/2) ?
The answer to (\partial)/(\partial y)(y/2) is 1/2