What is the tangent of f(x)=6e^xcos(x),\at x=0 ?

The tangent of f(x)=6e^xcos(x),\at x=0 is y=6x+6

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tangent of f(x)=6e^xcos(x),\at x=0

tangent of

f (x) = 6 e^{x} cos (x), at x = 0

y = 6 x + 6

Solution steps

Find the tangent point:

(0, 6)

Find the slope of

f (x) = 6 e^{x} cos (x) : \frac{df ( x )}{d x} = 6 (e^{x} cos (x) - e^{x} sin (x))

Compute the slope of

f (x) = 6 e^{x} cos (x)

x = 0 : m = 6

Find the line with slope m=

6

and passing through

(0, 6) : y = 6 x + 6

y = 6 x + 6

sin (2 x) cos (2 x)

\frac{d}{d x} (50 e^{4 x} + 300 e^{- 3 x})

\frac{\partial}{\partial x} (x^{2} e^{y})

e^{4 t s i n (2 t)}

\int \frac{x ^{2} + 3}{x ^{2} - 3 x + 2} d x

What is the tangent of f(x)=6e^xcos(x),\at x=0 ?
The tangent of f(x)=6e^xcos(x),\at x=0 is y=6x+6