What is the derivative of y=tan(5x^3) ?

The derivative of y=tan(5x^3) is sec^2(5x^3)*15x^2

What is the first derivative of y=tan(5x^3) ?

The first derivative of y=tan(5x^3) is sec^2(5x^3)*15x^2

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derivative of

y = tan (5 x^{3})

sec^{2} (5 x^{3}) \cdot 15 x^{2}

Solution steps

\frac{d}{d x} (tan (5 x^{3}))

Apply the chain rule:

sec^{2} (5 x^{3}) \frac{d}{d x} (5 x^{3})

= sec^{2} (5 x^{3}) \frac{d}{d x} (5 x^{3})

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

= sec^{2} (5 x^{3}) \cdot 15 x^{2}

\frac{\partial}{\partial x} (x \cdot cos (x))

\frac{\partial}{\partial x} (x cos (y) sin (z))

y = 6 4 + x

\frac{d}{d x} (\frac{cos ( x )}{x ^{2} + 1})

o 2 x 2 - 3 x + 2

What is the derivative of y=tan(5x^3) ?
The derivative of y=tan(5x^3) is sec^2(5x^3)*15x^2
What is the first derivative of y=tan(5x^3) ?
The first derivative of y=tan(5x^3) is sec^2(5x^3)*15x^2