What is the derivative of f(x)=-8x^3 ?

The derivative of f(x)=-8x^3 is -24x^2

What is the first derivative of f(x)=-8x^3 ?

The first derivative of f(x)=-8x^3 is -24x^2

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derivative of

f (x) = - 8 x^{3}

- 24 x^{2}

Solution steps

\frac{d}{d x} (- 8 x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 8 \cdot 3 x^{3 - 1}

Simplify

= - 24 x^{2}

\int \frac{x ^{2} + 7 x + 1}{( x ^{2} + 1 ) ^{2}} d x

\frac{\partial}{\partial y} (2 x y^{4} - 3)

\int \frac{x + 2}{x ^{2} + 5 x - 6} d x

\int_{0}^{1} x^{2} x d x

\frac{x}{x ^{2} - 7}

What is the derivative of f(x)=-8x^3 ?
The derivative of f(x)=-8x^3 is -24x^2
What is the first derivative of f(x)=-8x^3 ?
The first derivative of f(x)=-8x^3 is -24x^2