What is the derivative of (x^2-4^{2/3}) ?

The derivative of (x^2-4^{2/3}) is (4x)/(3(x^2-4)^{1/3)}

What is the first derivative of (x^2-4^{2/3}) ?

The first derivative of (x^2-4^{2/3}) is (4x)/(3(x^2-4)^{1/3)}

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Popular >

\frac{d}{d x} ((x^{2} - 4)^{\frac{2}{3}})

\frac{4 x}{3 ( x ^{2} - 4 ) ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} ((x^{2} - 4)^{\frac{2}{3}})

Apply the chain rule:

\frac{2}{3 ( x ^{2} - 4 ) ^{\frac{1}{3}}} \frac{d}{d x} (x^{2} - 4)

= \frac{2}{3 ( x ^{2} - 4 ) ^{\frac{1}{3}}} \frac{d}{d x} (x^{2} - 4)

\frac{d}{d x} (x^{2} - 4) = 2 x

= \frac{2}{3 ( x ^{2} - 4 ) ^{\frac{1}{3}}} \cdot 2 x

Simplify

\frac{2}{3 ( x ^{2} - 4 ) ^{\frac{1}{3}}} \cdot 2 x : \frac{4 x}{3 ( x ^{2} - 4 ) ^{\frac{1}{3}}}

= \frac{4 x}{3 ( x ^{2} - 4 ) ^{\frac{1}{3}}}

sin (b x)

2 x - 1

\int \frac{1}{x ^{2} - 6 x + 13} d x

y^{^{''}} + 2 y^{^{'}} = 0, y (0) = - 4, y^{^{'}} (0) = 2

\frac{\partial}{\partial x} (x^{2} \cdot y)

What is the derivative of (x^2-4^{2/3}) ?
The derivative of (x^2-4^{2/3}) is (4x)/(3(x^2-4)^{1/3)}
What is the first derivative of (x^2-4^{2/3}) ?
The first derivative of (x^2-4^{2/3}) is (4x)/(3(x^2-4)^{1/3)}