What is the derivative of 3/(t^3) ?

The derivative of 3/(t^3) is -9/(t^4)

What is the first derivative of 3/(t^3) ?

The first derivative of 3/(t^3) is -9/(t^4)

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derivative of

\frac{3}{t ^{3}}

- \frac{9}{t ^{4}}

Solution steps

\frac{d}{d t} (\frac{3}{t ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (\frac{1}{t ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d t} (t^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 3 t^{- 3 - 1})

Simplify

3 (- 3 t^{- 3 - 1}) : - \frac{9}{t ^{4}}

= - \frac{9}{t ^{4}}

n = 0 \sum \infty \frac{x ^{2 n}}{n !}

\frac{d}{d x} (\frac{e ^{x}}{x cos ( x )})

(\frac{2 y}{x} + 2 x) + (2 ln (x) - 3) \frac{d y}{d x} = 0

\frac{d}{d x} (- x^{2} + 8 x - 12)

\frac{d}{d x} (2 x - 5)

What is the derivative of 3/(t^3) ?
The derivative of 3/(t^3) is -9/(t^4)
What is the first derivative of 3/(t^3) ?
The first derivative of 3/(t^3) is -9/(t^4)