What is the solution for ((2y)/x+2x)+(2ln(x)-3)(dy)/(dx)=0 ?

The solution for ((2y)/x+2x)+(2ln(x)-3)(dy)/(dx)=0 is y=-(x^2)/(2ln(x)-3)+(c_{1})/(2ln(x)-3)

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((2y)/x+2x)+(2ln(x)-3)(dy)/(dx)=0

(\frac{2 y}{x} + 2 x) + (2 ln (x) - 3) \frac{d y}{d x} = 0

y = - \frac{x ^{2}}{2 ln ( x ) - 3} + \frac{c _{1}}{2 ln ( x ) - 3}

Solution steps

(\frac{2 y}{x} + 2 x) + (2 ln (x) - 3) \frac{d y}{d x} = 0

Solve linear ODE:

y = - \frac{x ^{2}}{2 ln ( x ) - 3} + \frac{c _{1}}{2 ln ( x ) - 3}

y = - \frac{x ^{2}}{2 ln ( x ) - 3} + \frac{c _{1}}{2 ln ( x ) - 3}

\frac{d}{d x} (- x^{2} + 8 x - 12)

\frac{d}{d x} (2 x - 5)

y = x^{3} - 3 x + 5, (3, 23)

f (x) = \frac{x}{x ^{2} + 1}, at x = 0

\int \frac{1}{1 - v} d v

What is the solution for ((2y)/x+2x)+(2ln(x)-3)(dy)/(dx)=0 ?
The solution for ((2y)/x+2x)+(2ln(x)-3)(dy)/(dx)=0 is y=-(x^2)/(2ln(x)-3)+(c_{1})/(2ln(x)-3)