What is the derivative of arctan(-x) ?

The derivative of arctan(-x) is -1/(x^2+1)

What is the first derivative of arctan(-x) ?

The first derivative of arctan(-x) is -1/(x^2+1)

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\frac{d}{d x} (arctan (- x))

- \frac{1}{x ^{2} + 1}

Solution steps

\frac{d}{d x} (arctan (- x))

Apply the chain rule:

\frac{1}{( - x ) ^{2} + 1} \frac{d}{d x} (- x)

= \frac{1}{( - x ) ^{2} + 1} \frac{d}{d x} (- x)

\frac{d}{d x} (- x) = - 1

= \frac{1}{( - x ) ^{2} + 1} (- 1)

Simplify

\frac{1}{( - x ) ^{2} + 1} (- 1) : - \frac{1}{x ^{2} + 1}

= - \frac{1}{x ^{2} + 1}

8 e^{x} cos (x)

k = 0 \sum \infty (- \frac{3}{4})^{k}

\frac{d}{d x} (- (x - 1)^{2} + 3)

\frac{d}{d x} (\frac{12 x ^{6} - 3 x ^{2} + x ^{2}}{3 x ^{4}})

\int cos (x) \cdot sin^{2} (x) d x

What is the derivative of arctan(-x) ?
The derivative of arctan(-x) is -1/(x^2+1)
What is the first derivative of arctan(-x) ?
The first derivative of arctan(-x) is -1/(x^2+1)