What is the integral from 0 to 9 of (1/3 x-2) ?

The integral from 0 to 9 of (1/3 x-2) is -9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 9 of (1/3 x-2)

\int_{0}^{9} (\frac{1}{3} x - 2) d x

- \frac{9}{2}

Decimal Notation

- 4.5

Solution steps

\int_{0}^{9} \frac{1}{3} x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{9} \frac{1}{3} x d x - \int_{0}^{9} 2 d x

\int_{0}^{9} \frac{1}{3} x d x = \frac{27}{2}

\int_{0}^{9} 2 d x = 18

= \frac{27}{2} - 18

Simplify

\frac{27}{2} - 18 : - \frac{9}{2}

= - \frac{9}{2}

(5 + x) y^{^{'}} - y = 0

\int u - 1 d u

\int \frac{tan ( ln ( 4 x + 3 ) )}{4 x + 3} d x

\frac{\partial}{\partial y} (tan (1 + 2 x^{2} y^{3} z^{2}))

(x + \frac{1}{x})^{^{'}}

What is the integral from 0 to 9 of (1/3 x-2) ?
The integral from 0 to 9 of (1/3 x-2) is -9/2