en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(5+x)y^'-y=0

Solution

(5 + x) y^{^{'}} - y = 0

Solution

y = 5 e^{c_{1}} + e^{c_{1}} x

Solution steps

(5 + x) y^{'} (x) - y = 0

Solve separable ODE:

y = 5 e^{c_{1}} + e^{c_{1}} x

y = 5 e^{c_{1}} + e^{c_{1}} x

Popular Examples

integral of u-1

\int u - 1 d u

integral of (tan(ln(4x+3)))/(4x+3)

\int \frac{tan ( ln ( 4 x + 3 ) )}{4 x + 3} d x

(\partial)/(\partial y)(tan(1+2x^2y^3z^2))

\frac{\partial}{\partial y} (tan (1 + 2 x^{2} y^{3} z^{2}))

(x + \frac{1}{x})^{^{'}}

derivative of [x+(x+sin^2(x))^3]^5 derivative of

[x + (x + sin^{2} (x))^{3}]^{5}

Frequently Asked Questions (FAQ)

What is the solution for (5+x)y^'-y=0 ?
The solution for (5+x)y^'-y=0 is y=5e^{c_{1}}+e^{c_{1}}x