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Popular >

y^{''}-y^'-30=0

Solution

y^{^{''}} - y^{^{'}} - 30 = 0

Solution

y = c_{1} e^{t} + c_{2} - 30 t

Solution steps

y^{''} (t) - y^{'} (t) - 30 = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} - 30 t

y = c_{1} e^{t} + c_{2} - 30 t

Popular Examples

derivative of 569+t(37t^{0.6}-108)derivative of

569 + t (37 t^{0.6} - 108)

(dr)/(dθ)=(r^2+10rθ)/(5θ^2)

\frac{d r}{d θ} = \frac{r ^{2} + 10 r θ}{5 θ ^{2}}

integral of 5e^{2x-1}

\int 5 e^{2 x - 1} d x

y^{''}-18y^'+77y=0

y^{^{''}} - 18 y^{^{'}} + 77 y = 0

integral of x^{-2}ln(x)

\int x^{- 2} ln (x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'-30=0 ?
The solution for y^{''}-y^'-30=0 is y=c_{1}e^t+c_{2}-30t