What is the derivative of ln(x+b) ?

The derivative of ln(x+b) is 1/(x+b)

What is the first derivative of ln(x+b) ?

The first derivative of ln(x+b) is 1/(x+b)

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\frac{d}{d x} (ln (x + b))

\frac{1}{x + b}

Solution steps

\frac{d}{d x} (ln (x + b))

Apply the chain rule:

\frac{1}{x + b} \frac{d}{d x} (x + b)

= \frac{1}{x + b} \frac{d}{d x} (x + b)

\frac{d}{d x} (x + b) = 1

= \frac{1}{x + b} \cdot 1

Simplify

= \frac{1}{x + b}

\frac{d}{d x} (x^{2} + x - 1)

\int (3 - \frac{1}{x ^{4}}) d x

\frac{d}{d x} (cos (2 x) d x)

\frac{d}{d x} ((x^{2} - 2)^{2})

\frac{11 - x}{7} + \frac{36 + x ^{2}}{3}

What is the derivative of ln(x+b) ?
The derivative of ln(x+b) is 1/(x+b)
What is the first derivative of ln(x+b) ?
The first derivative of ln(x+b) is 1/(x+b)