What is the derivative of cos(2xdx) ?

The derivative of cos(2xdx) is d(-2xsin(2x)+cos(2x))

What is the first derivative of cos(2xdx) ?

The first derivative of cos(2xdx) is d(-2xsin(2x)+cos(2x))

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\frac{d}{d x} (cos (2 x) d x)

d (- 2 x sin (2 x) + cos (2 x))

Solution steps

\frac{d}{d x} (cos (2 x) d x)

Treat

d

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= d \frac{d}{d x} (cos (2 x) x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = cos (2 x), g = x

= d (\frac{d}{d x} (cos (2 x)) x + \frac{d x}{d x} cos (2 x))

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

\frac{d x}{d x} = 1

= d ((- sin (2 x) \cdot 2) x + 1 \cdot cos (2 x))

Simplify

= d (- 2 x sin (2 x) + cos (2 x))

\frac{d}{d x} ((x^{2} - 2)^{2})

\frac{11 - x}{7} + \frac{36 + x ^{2}}{3}

\int_{0}^{9} ∣ 2 x - 9 ∣ d x

x \to 3 - lim (\frac{e ^{2}}{x - 3})

\int \frac{x ^{2}}{( 1 - x ^{3} ) ^{5}} d x

What is the derivative of cos(2xdx) ?
The derivative of cos(2xdx) is d(-2xsin(2x)+cos(2x))
What is the first derivative of cos(2xdx) ?
The first derivative of cos(2xdx) is d(-2xsin(2x)+cos(2x))