What is (\partial)/(\partial x)(6sin(xy)) ?

The answer to (\partial)/(\partial x)(6sin(xy)) is 6cos(xy)y

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(\partial)/(\partial x)(6sin(xy))

\frac{\partial}{\partial x} (6 sin (x y))

6 cos (x y) y

Solution steps

\frac{\partial}{\partial x} (6 sin (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{\partial}{\partial x} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial x} (x y)

= cos (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= 6 cos (x y) y

\frac{d}{d x} ((\frac{x + 3}{x - 3})^{4})

\frac{\partial}{\partial x} (\frac{y - z}{x})

\int_{0}^{1} (x - x)^{2} d x

\frac{s - 4}{s ^{2} - 8 s + 10}

t^{\frac{4}{3}}

What is (\partial)/(\partial x)(6sin(xy)) ?
The answer to (\partial)/(\partial x)(6sin(xy)) is 6cos(xy)y